document.write( "Question 546144: Solve. Check for extraneous solutions.\r
\n" ); document.write( "\n" ); document.write( "Question: Square root of quantity (3x+7)= x - 1\r
\n" ); document.write( "\n" ); document.write( "I keep getting x= 2 or -3, but when I check it they numbers dont work out. Please show all the steps.\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #355892 by ankor@dixie-net.com(22740)\"\" \"About 
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Square root of quantity \"sqrt%283x%2B7%29\" = x - 1
\n" ); document.write( "Square both sides
\n" ); document.write( "3x + 7 = (x-1)^2
\n" ); document.write( "FOIL the right side
\n" ); document.write( "3x + 7 = x^2 - 2x + 1
\n" ); document.write( "Combine like terms on the right
\n" ); document.write( "0 = x^2 - 2x - 3x + 1 - 7
\n" ); document.write( "A quadratic equation
\n" ); document.write( "x^2 - 5x - 6 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-6)(x+1) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 6
\n" ); document.write( "x = -1
\n" ); document.write( "Check both solutions in the original equation
\n" ); document.write( "x=6
\n" ); document.write( "\"sqrt%283%286%29%2B7%29\" = 6 - 1
\n" ); document.write( "\"sqrt%2825%29\" = 6 - 1
\n" ); document.write( "5 = 5; x=6 is a good solution
\n" ); document.write( "x=-1
\n" ); document.write( "\"sqrt%283%28-1%29%2B7%29\" = -1 - 1
\n" ); document.write( "\"sqrt%284%29\" = -2
\n" ); document.write( "2 = -2, an extraneous solution
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