document.write( "Question 546144: Solve. Check for extraneous solutions.\r
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document.write( "Question: Square root of quantity (3x+7)= x - 1\r
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document.write( "I keep getting x= 2 or -3, but when I check it they numbers dont work out. Please show all the steps.\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #355892 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Square root of quantity \n" ); document.write( "Square both sides \n" ); document.write( "3x + 7 = (x-1)^2 \n" ); document.write( "FOIL the right side \n" ); document.write( "3x + 7 = x^2 - 2x + 1 \n" ); document.write( "Combine like terms on the right \n" ); document.write( "0 = x^2 - 2x - 3x + 1 - 7 \n" ); document.write( "A quadratic equation \n" ); document.write( "x^2 - 5x - 6 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x-6)(x+1) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "x = 6 \n" ); document.write( "x = -1 \n" ); document.write( "Check both solutions in the original equation \n" ); document.write( "x=6 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "5 = 5; x=6 is a good solution \n" ); document.write( "x=-1 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2 = -2, an extraneous solution \n" ); document.write( " |