document.write( "Question 545445: Solve.
\n" ); document.write( "4log₃2 - 2log₂x = 1\r
\n" ); document.write( "\n" ); document.write( "I attempted using the Power Property of Logarithms first, but then I got stuck because the bases of both logs were different.
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Algebra.Com's Answer #355872 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Solve.
\n" ); document.write( "4log₃2 - 2log₂x = 1
\n" ); document.write( "log3(2^4)-log2(x^2)=1
\n" ); document.write( "log3(16)-log2(x^2)=1
\n" ); document.write( "change to base 10
\n" ); document.write( "log(16)/log(3)-log(x^2)/log(2)=1
\n" ); document.write( "2.5237-log(x^2)/log(2)=1
\n" ); document.write( "2.5237-1=log(x^2)/log(2)
\n" ); document.write( "1.5237*log(2)=log(x^2)
\n" ); document.write( ".4587=log(x^2)
\n" ); document.write( "x^2=10^.4587=2.8754
\n" ); document.write( "x≈1.696
\n" ); document.write( "note: I tried solving without using a calculator but maybe a smarter tutor might know how.
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