document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=545618>Question 545618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please assist with the steps to solve this equation.  I know the answer, but want to see the steps to solve.  thanks...\r<BR>\n" );
document.write( "\n" );
document.write( "log(base 3)x + log(base 3)(x - 2) = 1\r<BR>\n" );
document.write( "\n" );
document.write( "Answer should be: 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355866 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(base 3)x + log(base 3)(x - 2) = 1<BR>\n" );
document.write( "log3(x)+log3(x-2)=1<BR>\n" );
document.write( "place under single log (addition in logs indicates multiplication in operations)<BR>\n" );
document.write( "log[x*(x-2)]=1<BR>\n" );
document.write( "log[x^2-2x]=1<BR>\n" );
document.write( "convert to exponential form: base(3) raised to log of number(1)=number[x^2-2x]<BR>\n" );
document.write( "3^1=[x^2-2x]<BR>\n" );
document.write( "x^2-2x-3=0<BR>\n" );
document.write( "(x-3)(x+1)=0<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=-1(reject, x>0)<BR>\n" );
document.write( "ans: x=3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );