document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546035>Question 546035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two numbers is 90. One number is 3 more than twice the other number. Use quadratics to determine what the numbers are. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355838 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The product of two numbers is 90. One number is 3 more than twice the other number. Use quadratics to determine what the numbers are.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "xy = 90<BR>\n" );
document.write( "x = 2y+3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Substitute and solve:<BR>\n" );
document.write( "(2y+3)y = 90<BR>\n" );
document.write( "2y^2+3y-90 = 0<BR>\n" );
document.write( "----<BR>\n" );
document.write( "y = [-3 +- sqrt(9-4*2*-90)]/4<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "y = [-3 + sqrt(729)]/4<BR>\n" );
document.write( "---<BR>\n" );
document.write( "y = [24/4]<BR>\n" );
document.write( "y = 6<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Solve for \"x\":<BR>\n" );
document.write( "x = 2y+3<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );