document.write( "Question 546005: (x-4)^2+16(y-5)=0 Does this line go through point (0,7)? And does this parabola open upwards? \n" ); document.write( "
Algebra.Com's Answer #355824 by lwsshak3(11628) ![]() You can put this solution on YOUR website! (x-4)^2+16(y-5)=0 Does this line go through point (0,7)? And does this parabola open upwards? \n" ); document.write( "** \n" ); document.write( "Standard form of an equation for a parabola that opens downwards: (x-h)^2=-4p(y-k), with (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( ".. \n" ); document.write( "Rewrite given equation: \n" ); document.write( "(x-4)^2=-16(y-5) \n" ); document.write( "This is the standard form of an equation for a parabola that opens downwards with vertex at (4,5) \n" ); document.write( ".. \n" ); document.write( "plug (0,7) into equation: \n" ); document.write( "(0-4)^2=-16(7-5) \n" ); document.write( "16≠-32 \n" ); document.write( "Therefore, (0,7) is not a point on the parabola \n" ); document.write( " |