document.write( "Question 546005: (x-4)^2+16(y-5)=0 Does this line go through point (0,7)? And does this parabola open upwards? \n" ); document.write( "
Algebra.Com's Answer #355824 by lwsshak3(11628)\"\" \"About 
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(x-4)^2+16(y-5)=0 Does this line go through point (0,7)? And does this parabola open upwards?
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\n" ); document.write( "Standard form of an equation for a parabola that opens downwards: (x-h)^2=-4p(y-k), with (h,k) being the (x,y) coordinates of the vertex.
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\n" ); document.write( "Rewrite given equation:
\n" ); document.write( "(x-4)^2=-16(y-5)
\n" ); document.write( "This is the standard form of an equation for a parabola that opens downwards with vertex at (4,5)
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\n" ); document.write( "plug (0,7) into equation:
\n" ); document.write( "(0-4)^2=-16(7-5)
\n" ); document.write( "16≠-32
\n" ); document.write( "Therefore, (0,7) is not a point on the parabola
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