document.write( "Question 545868: Find the equation of the line which is perpendicular to 3x-7y=-4 and passes through the point (-6,1) \n" ); document.write( "
Algebra.Com's Answer #355773 by mananth(16946)\"\" \"About 
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3x-7y=-4 and passes through the point (-6,1)\r
\n" ); document.write( "\n" ); document.write( "3 x -7 y = -4
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-7 y = -3 x -4
\n" ); document.write( "Divide by -7
\n" ); document.write( " y = 3/ 7 x + 0.57
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 3/7
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -2.33
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be -7/3
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\n" ); document.write( "m= -7/3 ,point (-6,1)
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "1 = 14.00 + b
\n" ); document.write( "b= -13
\n" ); document.write( "m= -7/3
\n" ); document.write( "The required equation is y =-7/3 x-13
\n" ); document.write( "m.ananth@hotmail.ca
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