document.write( "Question 545854: A sidewalk vendor has 3 items on sale namely, a pocketbook for $50,a wall clock at $30, and a pencil at $1. At the end of the day he has sold a total of 100 items for a total sale of $1000. How many pocketbooks were sold? \n" ); document.write( "

Algebra.Com's Answer #355771 by JBarnum(2146) $\"\"$ $\"About$

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50b+30w+p=1000
\n" ); document.write( "b+w+p=100\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "not enough info so imma guess n check
\n" ); document.write( "with looking at top equation if the were no wall clocks sold or pencils the most amount of pocketbooks couls be 1000/50=20, same procedure for wall clocks is 1000/30=33, pencils would be 1000.
\n" ); document.write( "so we know that theres: b<20 w<30 and p<1000
\n" ); document.write( "looking at second equation p<100
\n" ); document.write( "b w p
\n" ); document.write( "10+10+80=100
\n" ); document.write( "500+300+80=880
\n" ); document.write( "wrong
\n" ); document.write( "5+5+90=100
\n" ); document.write( "250+150+90=490
\n" ); document.write( "wrong
\n" ); document.write( "20+30+50=100
\n" ); document.write( "1000+900+50=1950
\n" ); document.write( "wrong
\n" ); document.write( "15+5+80=100
\n" ); document.write( "750+150+80=980
\n" ); document.write( "wrong
\n" ); document.write( "16+4+80=100
\n" ); document.write( "800+120+80=1000
\n" ); document.write( "correct.....yes found it
\n" ); document.write( "16 pocketbooks 4 wall clocks and 80 pencils sold \n" ); document.write( "

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