document.write( "Question 545751: A total of $12,000 is invested in two funds paying 3% and 3.4% simple interest. The annual interest is $378. How much is invested in each fund?\r
\n" ); document.write( "\n" ); document.write( "Can you show the steps as well so I can figure out how to do it myself? Thank you!
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Algebra.Com's Answer #355760 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Fund A 3.00% per annum ---x
\n" ); document.write( "Fund B 3.40% per annum ---y
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\n" ); document.write( "x + y= 12000 ------------------------1
\n" ); document.write( "3.00% x + 3.40% y= = $378.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "3 x + 3.4 y= = $37,800.00 --------2
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\n" ); document.write( "Multiply (1) by -3
\n" ); document.write( "we get
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\n" ); document.write( "-3 x -3 y= = -36000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x 0.4 y= = $1,800.00
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\n" ); document.write( "divide by 0.4
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\n" ); document.write( "y = $4,500.00 investment at 3.40%
\n" ); document.write( "Balance $7,500.00investment at 3.00%
\n" ); document.write( "CHECK
\n" ); document.write( "$7,500.00 --------- 3.00% ------- $225.00
\n" ); document.write( "$4,500.00 ------- 3.40% ------- $153.00
\n" ); document.write( "Total -------------- $378.00 \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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