document.write( "Question 545751: A total of $12,000 is invested in two funds paying 3% and 3.4% simple interest. The annual interest is $378. How much is invested in each fund?\r
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document.write( "Can you show the steps as well so I can figure out how to do it myself? Thank you! \n" );
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Algebra.Com's Answer #355760 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Fund A 3.00% per annum ---x \n" ); document.write( "Fund B 3.40% per annum ---y \n" ); document.write( " \n" ); document.write( "x + y= 12000 ------------------------1 \n" ); document.write( "3.00% x + 3.40% y= = $378.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "3 x + 3.4 y= = $37,800.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -3 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-3 x -3 y= = -36000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0 x 0.4 y= = $1,800.00 \n" ); document.write( " \n" ); document.write( "divide by 0.4 \n" ); document.write( " \n" ); document.write( "y = $4,500.00 investment at 3.40% \n" ); document.write( "Balance $7,500.00investment at 3.00% \n" ); document.write( "CHECK \n" ); document.write( "$7,500.00 --------- 3.00% ------- $225.00 \n" ); document.write( "$4,500.00 ------- 3.40% ------- $153.00 \n" ); document.write( "Total -------------- $378.00 \r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |