document.write( "Question 53314: find the vertex of: f(x)=3x^2-6x+8 \n" ); document.write( "
Algebra.Com's Answer #35574 by stanbon(75887)\"\" \"About 
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find the vertex of: f(x)=3x^2-6x+8
\n" ); document.write( "Rewrite as:
\n" ); document.write( "3x^2-6x+? = y-8
\n" ); document.write( "Rewrite as:
\n" ); document.write( "3(x^2-2x+?=y-8
\n" ); document.write( "Rewrite as :
\n" ); document.write( "(x^2-2x+? =(1/3)(y-8)
\n" ); document.write( "Complete the square:
\n" ); document.write( "x^2-2x+1 = (1/3)(y-8)+1
\n" ); document.write( "(x-1)^2=(1/3)(y-8+3)
\n" ); document.write( "(x-1)^2=(1/3)(y-5)
\n" ); document.write( "Vertex is at (1,5)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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