document.write( "Question 545573: Hello, could you please help me figure out where I am going wrong with the foci and vertices of \"+25x%5E2-4y%5E2%2B50x%2B16y=+91+\". I keep getting an \"a\" of 2 and a \"b\" of 5 (with \"c\" being sqrt( 29 ) ) but my calculator's graph says it should be different (an \"a\" of 1/2). Thank you. \n" ); document.write( "
Algebra.Com's Answer #355731 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Find Foci and Vertices
\n" ); document.write( "25x^2-4y^2+50x+16y= 91
\n" ); document.write( "**
\n" ); document.write( "25x^2+50x+-4y^2+16y= 91
\n" ); document.write( "complete the square
\n" ); document.write( "25(x^2+2x+1)-4(y^2-4y+4)= 91+25-16=100
\n" ); document.write( "25(x+1)^2-4(y-2)^2=100
\n" ); document.write( "divide by 100
\n" ); document.write( "(x+1)^2/4-(y-2)^2/25=1
\n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis of the standard form:
\n" ); document.write( "(x-h)^2/a^2-(y-k)^2/b^2=1
\n" ); document.write( "For given equation:
\n" ); document.write( "center:(-1,2)
\n" ); document.write( "..
\n" ); document.write( "a^2=4
\n" ); document.write( "a=2
\n" ); document.write( "vertices: (-1±a, 2)=(-1±2,2)=(-3,2) and (1,2)
\n" ); document.write( "..
\n" ); document.write( "b^2=25
\n" ); document.write( "b=5
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2=4+25=29
\n" ); document.write( "c=√29≈5.4
\n" ); document.write( "Foci: (-1±√29,2), (-1±6.4,2)=(-7.4,2) and (5.4,2)\r
\n" ); document.write( "\n" ); document.write( "Seems like you got a, b, and c correct. Maybe you did not punched the right data into your graphing calculator.
\n" ); document.write( "
\n" );