document.write( "Question 545731: The length of a rectangle is twice the width. The area is 450yd^2. Find the length and width.\r
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document.write( "I tried 900 and 225, but I am not sure that is correct. \n" );
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Algebra.Com's Answer #355687 by saifoo.khan(162)![]() ![]() You can put this solution on YOUR website! Hello,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L=2W \n" ); document.write( "A=LW \n" ); document.write( "REPLACE L WITH 2W & SOLCE FOIR W. \n" ); document.write( "450=2W*W\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "2W^2=450 \n" ); document.write( "W^2=250/2 \n" ); document.write( "W^2=225 \n" ); document.write( "W=SQRT225 \n" ); document.write( "W=15 ANS.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Saifoo.khan \n" ); document.write( "einstein.saifoo@gmail.com \n" ); document.write( " |