document.write( "Question 545691: Salt is to be added to a 4% salt solution. How many ounces of salt and how many ounces of the 4% solution should be mixed together to get 60 ounces of a 20% salt solution? \n" ); document.write( "

Algebra.Com's Answer #355675 by oberobic(2304) $\"\"$ $\"About$

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60 ounces of a 20% salt solution will have .2*60 = 12 oz. salt
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\n" ); document.write( "x = amount of 4% salt solution
\n" ); document.write( "60 -x = amount of pure salt to add.
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\n" ); document.write( "4%*x + 100%(60-x) = 12
\n" ); document.write( ".04*x + 100*(60-x) = 12
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\n" ); document.write( "Multiply both sides by 100 to eliminate decimals.
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\n" ); document.write( "4x +6000 - 100x = 1200
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\n" ); document.write( "-96x = -4800
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\n" ); document.write( "x = -4800/-96
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\n" ); document.write( "x = 50
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\n" ); document.write( "50*.04 = 2 oz pure salt in 50 oz. of 4% salt solution
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\n" ); document.write( "60-50 = 10 oz pure salt to add to the 50 oz of 4% salt solution to make the required 60 oz of 20% solution.
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\n" ); document.write( "Answer: 50 oz. 4% + 10 oz. pure salt solution.
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\n" ); document.write( "Done. \n" ); document.write( "

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