document.write( "Question 545619: I really need help with this! I don't understand it and I have been working at it for like 30 minutes now thanks\r
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document.write( "Carlos wants to build a hot tub with a volume of 1000 cubic feet. What is a good approximation for the radius of the hot tub? \n" );
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Algebra.Com's Answer #355646 by mananth(16946)![]() ![]() You can put this solution on YOUR website! We have to assume the height. \n" ); document.write( "The standard height is 3 feet.\r \n" ); document.write( "\n" ); document.write( "volume of tub = pi*r^2*h\r \n" ); document.write( "\n" ); document.write( "1000= pi*r^2*h \n" ); document.write( "1000/(pi*h)=r^2 \n" ); document.write( "1000/(pi*3)=r^2\r \n" ); document.write( "\n" ); document.write( "r= sqrt(1000/(3*pi)) \n" ); document.write( "r= 10.3 feet \n" ); document.write( ".. \n" ); document.write( "if you increase height the diamter will decrease \n" ); document.write( " |