document.write( "Question 545619: I really need help with this! I don't understand it and I have been working at it for like 30 minutes now thanks\r
\n" ); document.write( "\n" ); document.write( "Carlos wants to build a hot tub with a volume of 1000 cubic feet. What is a good approximation for the radius of the hot tub?
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Algebra.Com's Answer #355646 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
We have to assume the height.
\n" ); document.write( "The standard height is 3 feet.\r
\n" ); document.write( "\n" ); document.write( "volume of tub = pi*r^2*h\r
\n" ); document.write( "\n" ); document.write( "1000= pi*r^2*h
\n" ); document.write( "1000/(pi*h)=r^2
\n" ); document.write( "1000/(pi*3)=r^2\r
\n" ); document.write( "\n" ); document.write( "r= sqrt(1000/(3*pi))
\n" ); document.write( "r= 10.3 feet
\n" ); document.write( "..
\n" ); document.write( "if you increase height the diamter will decrease
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