document.write( "Question 545623: Solve for P\r
\n" ); document.write( "\n" ); document.write( "q = p / √((p^2)+1) \n" ); document.write( "

Algebra.Com's Answer #355639 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"q+=+p+%2F+sqrt%28%28p%5E2%29%2B1%29\"$ \r
\n" ); document.write( "\n" ); document.write( "take the square of both sides\r
\n" ); document.write( "\n" ); document.write( " $\"q%5E2=p%5E2%2F%28p%5E2%2B1%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28p%5E2%2B1%29%2Fp%5E2=1%2Fq%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28p%5E2%2Fp%5E2%29+%2B%281%2Fp%5E2%29=+1%2Fq%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1%2B%281%2Fp%5E2%29=1%2Fq%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1%2Fp%5E2=+%28%281%2Fq%5E2%29-1%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1%2Fp%5E2=%281-q%5E2%29%2Fq%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"p%5E2=q%5E2%2F%281-q%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Take the square root\r
\n" ); document.write( "\n" ); document.write( " $\"p=%2B%28q%2F%28sqrt%281-q%5E2%29%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( "OR\r
\n" ); document.write( "\n" ); document.write( " $\"p=-%28q%2F%28sqrt%281-q%5E2%29%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \r
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