document.write( "Question 545578: A ball is thrown straight upin the air from a height of 6 feet at a speed of 80 feet per second. The height of the ball in feet is given by -16t^2 + 80t + 6 where t is the time in seconds. What is the height of the ball after 3 seconds \n" ); document.write( "

Algebra.Com's Answer #355626 by jerryguo41(197) $\"\"$ $\"About$

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$\"-16t%5E2%2B80t%2B6\"$
\n" ); document.write( "1) Basic physics formula for anything that has initial velocity is
\n" ); document.write( " $\"-16%28t%29%5E2%2Bvt%2Bh\"$ t= number of seconds; x= inital velocity (i.e. how hard was it thrown); h= initial height
\n" ); document.write( "2)Plug three in where you see a \"t\"
\n" ); document.write( " $\"-16%283%29%5E2%2B80%283%29%2B6\"$
\n" ); document.write( "3) Square then multiply
\n" ); document.write( " $\"-16%289%29%2B80%283%29%2B6\"$
\n" ); document.write( " $\"-144%2B240%2B6\"$
\n" ); document.write( "4) Simplify
\n" ); document.write( " $\"102\"$
\n" ); document.write( "5) At three seconds the ball is 102ft off the ground \n" ); document.write( "

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