document.write( "Question 545349: $10 is invested semiannually for 29 years at 5.5 % compounded semiannually. How much would the accumulated amount be? \n" ); document.write( "
Algebra.Com's Answer #355565 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"A=P%281%2Br%2Fn%29%5E%28n%2At%29\" Start with the compound interest formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=10%281%2B0.055%2F2%29%5E%282%2A29%29\" Plug in \"P=10\", \"r=0.055\" (the decimal equivalent of 5.5%), \"n=2\" and \"t=29\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=10%281%2B0.0275%29%5E%282%2A29%29\" Evaluate \"0.055%2F2\"} to get \"0.0275\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=10%281.0275%29%5E%282%2A29%29\" Add \"1\" to \"0.0275\" to get \"1.0275\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=10%281.0275%29%5E%2858%29\" Multiply \"2\" and \"29\" to get \"58\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=10%284.82332106540981%29\" Evaluate \"%281.0275%29%5E%2858%29\" to get \"4.82332106540981\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=48.2332106540981\" Multiply \"10\" and \"4.82332106540981\" to get \"48.2332106540981\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=48.23\" Round to the nearest hundredth (ie to the nearest penny).\r
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\n" ); document.write( "\n" ); document.write( "So the accumulated amount would be $48.23
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