document.write( "Question 545299: 1. Convert the binary number 111,000,111 into the base ten equivalent.\r
\n" ); document.write( "\n" ); document.write( "2. Convert the base ten number 111 into the binary equivalent.\r
\n" ); document.write( "\n" ); document.write( "3. Convert the decimal number 0.35743574357435743574357435743574 to a fraction
\n" ); document.write( "

Algebra.Com's Answer #355552 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
1. Convert the binary number 111000111 into the base ten equivalent.
\n" ); document.write( "
\r\n" );
document.write( " 1     1      1      0     0      0      1     1      1 \r\n" );
document.write( "\r\n" );
document.write( "1*28 + 1*27 + 1*26 + 0*25 + 0*24 + 0*23 + 1*22 + 1*21 + 1*20\r\n" );
document.write( " 258 +  128 +  64  + 0  +  0  +   0  +   4  +  2   +  1   = 457\r\n" );
document.write( "

\n" ); document.write( "2. Convert the base ten number 111 into the binary equivalent.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Keep dividing by 2 putting the quotients underneath and the\r\n" );
document.write( "remainder out to the right beside the quotient.  Quit when\r\n" );
document.write( "the quotient becoms 0.  Then the digits of the binary number\r\n" );
document.write( "are the remainders reading from bottom to top:\r\n" );
document.write( "\r\n" );
document.write( "   2)111\r\n" );
document.write( "    2)55  1\r\n" );
document.write( "    2)27  1\r\n" );
document.write( "    2)13  1\r\n" );
document.write( "     2)6  0\r\n" );
document.write( "     2)3  1\r\n" );
document.write( "     2)1  1\r\n" );
document.write( "       0  1    \r\n" );
document.write( "   \r\n" );
document.write( "List the remainders from bottom to top\r\n" );
document.write( "\r\n" );
document.write( "Answer:  1110111 \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "3. Convert the decimal number 0.35743574357435743574357435743574...\r\n" );
document.write( "   to a fraction\r\n" );
document.write( "\r\n" );
document.write( "       N = 0.35743574357435743574357435743574...\r\n" );
document.write( "\r\n" );
document.write( "There are four repeating digits so multiply both sides by 104 or 10000\r\n" );
document.write( "\r\n" );
document.write( " 10000N = 3574.3574357435743574357435743574...\r\n" );
document.write( "\r\n" );
document.write( "Subtract the original equation for N\r\n" );
document.write( "\r\n" );
document.write( " 10000N = 3574.35743574357435743574357435743574...\r\n" );
document.write( "      N =    0.35743574357435743574357435743574...\r\n" );
document.write( "--------------------------------------------------\r\n" );
document.write( "  9999N = 3574\r\n" );
document.write( "\r\n" );
document.write( "      N = \"3574%2F9999\"  It doesn't reduce.   \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );