document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544067>Question 544067</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sec theta = 13/12\r<BR>\n" );
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document.write( "what is sec theta/2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355526 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if sec x = 13/12 <BR>\n" );
document.write( "what is sec x/2?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "work with more familiar cos function:<BR>\n" );
document.write( "sec x = 13/12<BR>\n" );
document.write( "cos x = 12/13 (reciprocal of sec x)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "sec x/2=1/cos x/2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "cos x/2=&#8730;[(1+cos x)/2]=&#8730;[(1+12/13)/2]=&#8730;[(25/13)/2]=&#8730;(25/26)=&#8730;25/&#8730;26<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "sec x/2=1/cos x/2=&#8730;26/&#8730;25 </SPAN>\n" );
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