document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544933>Question 544933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the cos of theta if csc = 2/sqrt(3) and theta terminates in Q4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355520 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the cos of theta if csc = 2/sqrt(3) and theta terminates in Q4<BR>\n" );
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document.write( "csc and sin<0 in Q4, cos>0 in Q4<BR>\n" );
document.write( "cscx=-2/&#8730;3<BR>\n" );
document.write( "sinx=-&#8730;3/2 (reciprocal of csc)<BR>\n" );
document.write( "cos^2x=1-sin^2x=1-(-&#8730;3/2)^2=1-3/4=1/4<BR>\n" );
document.write( "cosx=&#8730;(1/4)=1/2 </SPAN>\n" );
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