document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=545148>Question 545148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Its a chem problem.\r<BR>\n" );
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document.write( "9.00=9.25 + log(x/.0375)\r<BR>\n" );
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document.write( "Solved on my calc to get aproxx .0215 but I want to know why. I am forgetting some basic rules of solving logs.\r<BR>\n" );
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document.write( "-.25 = logx - log(.0375) ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355509 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -.25 = logx - log(.0375) ?<BR>\n" );
document.write( "-.25 = logx/(.0375)<BR>\n" );
document.write( "10^(-.25) = x/(.0375)<BR>\n" );
document.write( ".0375*10^(-0.25) = x<BR>\n" );
document.write( "0.0211 = x<BR>\n" );
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