document.write( "Question 53285: Will you please solve the system by addition or substitution
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document.write( "3x-4y=8
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document.write( "6x-2y=10
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document.write( "thankyou \n" );
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Algebra.Com's Answer #35549 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! 3x-4y=8 \n" ); document.write( "6x-2y=10 \n" ); document.write( "------------------- \n" ); document.write( "multiply the 1st equation by -2 \n" ); document.write( "-2(3x-4y)=-2(8) \n" ); document.write( "Now your system is: \n" ); document.write( "-6x+8y=-16 \n" ); document.write( "6x-2y=10 \n" ); document.write( "--------------------------- \n" ); document.write( "Add the two equations together: \n" ); document.write( "-6x+8y=-16 \n" ); document.write( "+6x-2y=10 \n" ); document.write( "______________ \n" ); document.write( "0x+6y=-6 \n" ); document.write( "6y=-6 \n" ); document.write( "6y/6=-6/6 \n" ); document.write( "y=-1 \n" ); document.write( "--------------------------- \n" ); document.write( "Substitute y=-1 into the original first equation and solve for x: \n" ); document.write( "3x-4(-1)=8 \n" ); document.write( "3x+4=8 \n" ); document.write( "3x+4-4=8-4 \n" ); document.write( "3x=4 \n" ); document.write( "3x/3=4/3 \n" ); document.write( "x=4/3 \n" ); document.write( "-------------------------- \n" ); document.write( "So the solution of this system is: (4/3,-1) \n" ); document.write( "You can substitute these back into both equations and see if it checks. \n" ); document.write( "3(4/3)-4(-1)=8 \n" ); document.write( "4+4=8 \n" ); document.write( "8=8 looks like we're right. \n" ); document.write( "6(4/3)-2(-1)=10 \n" ); document.write( "8+2=10 \n" ); document.write( "10=10 we're absolutely right! \n" ); document.write( " |