document.write( "Question 545107: how do we solve log8=logx+log(2x) \n" ); document.write( "

Algebra.Com's Answer #355475 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"Log%288%29+=+Log%28x%29%2BLog%282x%29\"$ Apply the \"Product rule\" to the right side:
\n" ); document.write( " $\"Log%5Bb%5D%28M%29%2BLog%5Bb%5D%28N%29+=+Log%5Bb%5D%28M%2AN%29\"$ .
\n" ); document.write( " $\"Log%288%29+=+Log%28x%2A2x%29\"$
\n" ); document.write( " $\"Log%288%29+=+Log%282x%5E2%29\"$ If $\"Log%5Bb%5D%28M%29+=+Log%5Bb%5D%28N%29\"$ then $\"M+=+N\"$
\n" ); document.write( " $\"8+=+2x%5E2\"$ Divide by 2.
\n" ); document.write( " $\"4+=+x%5E2\"$ Take the square root.
\n" ); document.write( " $\"2+=+x\"$ or $\"x+=+2\"$
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