document.write( "Question 544544: Using Radical Operations In Real Life\r
\n" ); document.write( "\n" ); document.write( " Triangle # 1
\n" ); document.write( " 6 inch (Left)/__\Hypotenuse=x (right side)
\n" ); document.write( " 9 inch (bottom) \r
\n" ); document.write( "\n" ); document.write( " Triangle # 2
\n" ); document.write( "7 inch (left) /__\Hypotenuse=x
\n" ); document.write( " 7 inch(bottom)\r
\n" ); document.write( "\n" ); document.write( "1)Using the Pythagorean theorem, find the length of each hypotenuse. Write the
\n" ); document.write( "length of each hypotenuse using radicals ( i.e. n√x ). (Show your work).
\n" ); document.write( "1)
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\n" ); document.write( "\n" ); document.write( "2) Without converting the hypotenuse lengths to a decimal, find the area of a
\n" ); document.write( "rectangle with a length equivalent to Hypotenuse #1 and a width equivalent to
\n" ); document.write( "Hypotenuse #2. Express your answer using radicals.\r
\n" ); document.write( "\n" ); document.write( "3) Find the ratio of Hypotenuse #1 to Hypotenuse #2. Express your answer using
\n" ); document.write( "radicals
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Algebra.Com's Answer #355449 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2=6%5E2%2B9%5E2=36%2B81=117\"--> \"x=sqrt%28117%29=sqrt%289%2A13%29=sqrt%289%29%2Asqrt%2813%29=3sqrt%2813%29\"
\n" ); document.write( " \"x%5E2=7%5E2%2B7%5E2=49%2B49=98\"--> \"x=sqrt%2898%29=sqrt%2849%2A2%29=sqrt%2849%29%2Asqrt%282%29=7sqrt%282%29\"
\n" ); document.write( "The area of rectangle with sides measuring \"3sqrt%2813%29\" and \"7sqrt%282%29\" is
\n" ); document.write( "\"%283sqrt%2813%29%29%2A%287sqrt%282%29%29=3%2A7%2Asqrt%2813%29%2Asqrt%282%29=21sqrt%2826%29\"
\n" ); document.write( "The ratio of the hypotenuse lengths found above is
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\n" ); document.write( "I multiplied times the factor \"1=sqrt%282%29%2Fsqrt%282%29\" to rationalize (meaning getting rid of square roots in the denominator).
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