document.write( "Question 545091: A principal of $3000 is invested at 6% interest, compounded annually. How much will the investment be worth after 12 years \n" ); document.write( "
Algebra.Com's Answer #355419 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! A=3000(1.06)^12 \n" ); document.write( "A=3000*2.0122 \n" ); document.write( "A=$6036.60 \n" ); document.write( " |