document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544979>Question 544979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "     log7 24 - log7 (x+5)= log7 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355378 by </B><A HREF=/tutors/aboutme.mpl?userid=cira554><B>cira554(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cira554><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cira554><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in logarithms we know that log(A/B)=logA-logB<BR>\n" );
document.write( "therefore our equation log7 24-log7 (x+5)=log7 8 can be translated to;<BR>\n" );
document.write( "log7 (24/x+5)=log7 8 <BR>\n" );
document.write( "since the logs are of the same base we are justified to say that,<BR>\n" );
document.write( "24/x+5=8<BR>\n" );
document.write( "when we crossmultiply we get,   24=8x+40<BR>\n" );
document.write( "                                8x=24-40<BR>\n" );
document.write( "                                8x=-16<BR>\n" );
document.write( "                                our x is therefore -2 </SPAN>\n" );
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