document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544948>Question 544948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> nancy made 76 and 58 on her first two algebra test and she has one more test in hte class. if she needs at least a 77 average to pass the course, what does she need to score on her third test to pass the course? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355353 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let her need x\r<BR>\n" );
document.write( "\n" );
document.write( "Total will be (76+58+x )\r<BR>\n" );
document.write( "\n" );
document.write( "Average = 77 of 3 tests\r<BR>\n" );
document.write( "\n" );
document.write( "(76+58+x )/3 = 77\r<BR>\n" );
document.write( "\n" );
document.write( "134+x=231<BR>\n" );
document.write( "x=231-134<BR>\n" );
document.write( "x=97\r<BR>\n" );
document.write( "\n" );
document.write( "she needs 97 \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );