document.write( "Question 544835: if the diameter of the cylindrical object is 8feet 3 inches in diameter and it it 563 feet 2 inches long how many gallons are contained in this area and what is the weight of the liquid \n" ); document.write( "
Algebra.Com's Answer #355347 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the diameter of the cylindrical object is 8feet 3 inches \n" ); document.write( "563 feet 2 inches long \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "volume of cylinder = pi*r^2*h\r \n" ); document.write( "\n" ); document.write( "diameter = 8ft 3 in \n" ); document.write( "radius = 4ft 1.5 inch \n" ); document.write( "=4 1/8 ft \n" ); document.write( "=33/8 ft \n" ); document.write( "... \n" ); document.write( "Length = 563 feet 2 inches \n" ); document.write( "=563 +1/6 ft \n" ); document.write( "=3379/6 ft\r \n" ); document.write( "\n" ); document.write( "Volume = pi* (33/8)^2*3379/6 \n" ); document.write( "= 30,104.73 cu.ft\r \n" ); document.write( "\n" ); document.write( "1cu.ft = 7.48 gallons (liquid)\r \n" ); document.write( "\n" ); document.write( "30,104.73 cu.ft=225,183 gallons\r \n" ); document.write( "\n" ); document.write( "how many gallons are contained in this area and what is \n" ); document.write( " |