document.write( "Question 544835: if the diameter of the cylindrical object is 8feet 3 inches in diameter and it it 563 feet 2 inches long how many gallons are contained in this area and what is the weight of the liquid \n" ); document.write( "
Algebra.Com's Answer #355347 by mananth(16946)\"\" \"About 
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the diameter of the cylindrical object is 8feet 3 inches
\n" ); document.write( "563 feet 2 inches long \r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "volume of cylinder = pi*r^2*h\r
\n" ); document.write( "\n" ); document.write( "diameter = 8ft 3 in
\n" ); document.write( "radius = 4ft 1.5 inch
\n" ); document.write( "=4 1/8 ft
\n" ); document.write( "=33/8 ft
\n" ); document.write( "...
\n" ); document.write( "Length = 563 feet 2 inches
\n" ); document.write( "=563 +1/6 ft
\n" ); document.write( "=3379/6 ft\r
\n" ); document.write( "\n" ); document.write( "Volume = pi* (33/8)^2*3379/6
\n" ); document.write( "= 30,104.73 cu.ft\r
\n" ); document.write( "\n" ); document.write( "1cu.ft = 7.48 gallons (liquid)\r
\n" ); document.write( "\n" ); document.write( "30,104.73 cu.ft=225,183 gallons\r
\n" ); document.write( "\n" ); document.write( "how many gallons are contained in this area and what is
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