document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544912>Question 544912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.the length of a rectangular field is 11m more than it's width. if the length is decreased by 12m and the width is increased by 10m, the area decreases by 24m2.find the length and the width of the field.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355342 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width =x<BR>\n" );
document.write( "length = x+11\r<BR>\n" );
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document.write( "length decreased by 12<BR>\n" );
document.write( "x+11-12<BR>\n" );
document.write( "=x-1\r<BR>\n" );
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document.write( "width = x+10\r<BR>\n" );
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document.write( "area dcreases by 24\r<BR>\n" );
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document.write( "Original area - changed area = 24\r<BR>\n" );
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document.write( "x(x+11)-(x-1)(x+10)=24<BR>\n" );
document.write( "x^2+11x-(x^2+9x-10)=24<BR>\n" );
document.write( "x^2+11x-x^2-9x+10=24<BR>\n" );
document.write( "2x+10=24<BR>\n" );
document.write( "2x=24-10<BR>\n" );
document.write( "2x=14<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x=7 m the width<BR>\n" );
document.write( "Length = x+11= 18m<BR>\n" );
document.write( "..<BR>\n" );
document.write( "126-102=24<BR>\n" );
document.write( "x=14/20<BR>\n" );
document.write( "x=7/10 </SPAN>\n" );
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