document.write( "Question 544837: I need help finding 2 consecutive natural numbers such that the difference of their reciprocals is 1/4 the reciprocal of the smaller number. \n" ); document.write( "
Algebra.Com's Answer #355249 by friesr(113)![]() ![]() ![]() You can put this solution on YOUR website! x \n" ); document.write( "x + 1 = \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Lets get a commone denominator: \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "Multiply both sides by x \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "-- \n" ); document.write( "x=3 \n" ); document.write( "=== \n" ); document.write( "Your numbers are 3 and 4 \n" ); document.write( "-- \n" ); document.write( "Check: \n" ); document.write( "1/3 - 1/4 = 1/4 * 1/3 \n" ); document.write( "- \n" ); document.write( "4/12 - 3/12 = 1/12 \n" ); document.write( "1/12 = 1/12 \n" ); document.write( " \n" ); document.write( " |