document.write( "Question 544256: Write an equation of the line that is parallel to the given line
\n" ); document.write( " y = x + 3 and the given point (5,0).\r
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\n" ); document.write( "Write an equation of the line that is parallel to the given line
\n" ); document.write( " y = 2x + 3 and the given point (-4,1).
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Algebra.Com's Answer #355238 by SwiftAlbatross(13)\"\" \"About 
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y = x + 3 has a slope of 1 since the coefficient in front of x is 1. Therefore, the parallel line also has a slope of 1. Knowing this, we just need to find the y-intercept to put the parallel line in the form y = mx + b. Since we know the slope and we have the x and y coordinates of the given point which the line passes through, let us plug these into the y = mx + b equation to find the unknown y-intercept, b. So,\r
\n" ); document.write( "\n" ); document.write( "y = mx + b
\n" ); document.write( "0 = 1*5 + b
\n" ); document.write( "0 = 5 + b
\n" ); document.write( "-5 = -5
\n" ); document.write( "-5 = b\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the parallel line is y = x - 5. The other problem is very similar to this. I will just do the math.
\n" ); document.write( "y = mx + b
\n" ); document.write( "1 = 2*-4 + b
\n" ); document.write( "1 = -8 + b
\n" ); document.write( "+8 = +8
\n" ); document.write( "9 = b\r
\n" ); document.write( "\n" ); document.write( "y = 2x + 9
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