document.write( "Question 544740: 24y^2+2y-2=0 \n" ); document.write( "
Algebra.Com's Answer #355203 by nyc_function(2741)\"\" \"About 
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24y^2+2y-2 = 0\r
\n" ); document.write( "\n" ); document.write( "Divide every term by 2.\r
\n" ); document.write( "\n" ); document.write( "2(12y^2 + y - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "12y^2 + y - 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "12y^2 + 4y - 3y - 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "12y^2 + 4y becomes 4y(3y + 1)\r
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\n" ); document.write( "\n" ); document.write( "-3y - 1 becomes -(3y + 1)\r
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\n" ); document.write( "\n" ); document.write( "(4y - 1)(3y + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "Set each factor to zero and solve for y.\r
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\n" ); document.write( "\n" ); document.write( "4y - 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "4y = 1\r
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\n" ); document.write( "\n" ); document.write( "y = 1/4\r
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\n" ); document.write( "\n" ); document.write( "3y + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "3y = -1\r
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\n" ); document.write( "\n" ); document.write( "y = -1/3\r
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\n" ); document.write( "\n" ); document.write( "The answer for y should be y = 1/4 and y = -1/3.\r
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