document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544604>Question 544604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of a rectangle is 5 ft more than twice its width and the area is 42 ft^2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355164 by </B><A HREF=/tutors/aboutme.mpl?userid=friesr><B>friesr(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=friesr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Width = x<BR>\n" );
document.write( "lenght = 2x+5<BR>\n" );
document.write( "---<BR>\n" );
document.write( "solve for x<BR>\n" );
document.write( "x * (2x+5) = 42<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2x^2 + 5x = 42<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2x^2 + 5x -42 = 0<BR>\n" );
document.write( "---<BR>\n" );
document.write( "(x+6)(2x-7)<BR>\n" );
document.write( "x=-6 or x = 7/2<BR>\n" );
document.write( "since a lenght cannot be a negative value<BR>\n" );
document.write( "x = 7/2<BR>\n" );
document.write( "now sub back in to 2x+5 for your lenght.<BR>\n" );
document.write( "=== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );