document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544179>Question 544179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are twenty women and fifteen men at a party. In how many distinct ways can you form ten couples consisting of one man and one woman?\r<BR>\n" );
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document.write( "I thought it would be 15C10 * 20C10 * 10! - you choose the men and the women; then the first woman has ten choices, the second has nine, etc. However, I'm not sure what really distinguishes this from a basic Fundamental Counting Theorem problem once you have chosen the men and women; under that interpretation, the 10! is unnecessary.\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355133 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Yes, u r right. \r<BR>\n" );
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document.write( "total number of ways =  15C10 * 20C10 * 10!\r<BR>\n" );
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document.write( "if any doubt, feel free to contact.. </SPAN>\n" );
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