document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544511>Question 544511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat can travel 20 mph in still water.  If the boat can travel 3 miles downstream in the same time it takes to travel 2 miles upstream, what is the rate of the current?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355115 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Boat speed	=	20	mph										<BR>\n" );
document.write( "current  speed	=	x	mph										<BR>\n" );
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document.write( "speed against	current	20	-	x									<BR>\n" );
document.write( "speed with	current	20	+	x									<BR>\n" );
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document.write( "Distance against	current	2	miles										<BR>\n" );
document.write( "Distance with 	current	3	miles										<BR>\n" );
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document.write( "t=d/r	time against = time with		current										<BR>\n" );
document.write( "2/(20-x	)=3/(20	+x)<BR>\n" );
document.write( "2(20+x	)=	3( 20-x	)			<BR>\n" );
document.write( "40+2x	=	60-3x 					<BR>\n" );
document.write( "3x	+2x=20								<BR>\n" );
document.write( "5x=20										<BR>\n" );
document.write( "/5												<BR>\n" );
document.write( "x =	4	mph	current  speed									<BR>\n" );
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