document.write( "Question 544498: I have test corrections for homework. On the test, it says - \r
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document.write( "Write an equation of the line, in point-slope form, that is perpendicular to 3x+y=7 and passes through (-6,2).\r
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document.write( "I have done this on the test - \r
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document.write( "3x+y=7 (-3x on both sides)
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document.write( "y=-3x-7 (plug in coordinates)
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document.write( "y-2=-3(x+6)\r
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document.write( "My teacher said that the -3 part is wrong, yet I don't see why.
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document.write( " Please Reply Soon
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document.write( " Student in Need \n" );
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Algebra.Com's Answer #355104 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Write an equation of the line, in point-slope form, that is perpendicular to 3x+y=7 and passes through (-6,2). \n" ); document.write( "** \n" ); document.write( "Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept \n" ); document.write( ".. \n" ); document.write( "Given equation: \n" ); document.write( "3x+y=7 \n" ); document.write( "y=-3x+7 \n" ); document.write( "slope=-3 \n" ); document.write( ".. \n" ); document.write( "Slope of line perpendicular to given equation=1/3 (negative reciprocal of -3) \n" ); document.write( "y=(1/3)x+b=x/3+b \n" ); document.write( "solving for b plugging in coordinates of given point (-6,2) \n" ); document.write( "2=-6/3+b \n" ); document.write( "2=-2+b \n" ); document.write( "b=4 \n" ); document.write( "Equation of perpendicular line: \n" ); document.write( "y=x/3+4 \n" ); document.write( " |