document.write( "Question 544461: okay so it says solve linear system using substitution
\n" ); document.write( "4x + 3y = -5
\n" ); document.write( "x = y - 3
\n" ); document.write( "

Algebra.Com's Answer #355097 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
using substitution
\n" ); document.write( "4x + 3y = -5
\n" ); document.write( "x = y - 3
\n" ); document.write( "------
\n" ); document.write( "Substitute for \"x\" and solve for \"y\":
\n" ); document.write( "4(y-3) + 3y = -5
\n" ); document.write( "4y-12+3y = -5
\n" ); document.write( "7y = 7
\n" ); document.write( "y = 1
\n" ); document.write( "----
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x = y-3
\n" ); document.write( "x = 1-3
\n" ); document.write( "x = -2
\n" ); document.write( "--------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "============
\n" ); document.write( "
\n" );