document.write( "Question 544461: okay so it says solve linear system using substitution
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document.write( "4x + 3y = -5
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document.write( "x = y - 3 \n" );
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Algebra.Com's Answer #355097 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! using substitution \n" ); document.write( "4x + 3y = -5 \n" ); document.write( "x = y - 3 \n" ); document.write( "------ \n" ); document.write( "Substitute for \"x\" and solve for \"y\": \n" ); document.write( "4(y-3) + 3y = -5 \n" ); document.write( "4y-12+3y = -5 \n" ); document.write( "7y = 7 \n" ); document.write( "y = 1 \n" ); document.write( "---- \n" ); document.write( "Solve for \"x\": \n" ); document.write( "x = y-3 \n" ); document.write( "x = 1-3 \n" ); document.write( "x = -2 \n" ); document.write( "-------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |