document.write( "Question 544329: find four consecutive odd integers such that the sum of the first three exceeds the fourth by 18. \n" ); document.write( "
Algebra.Com's Answer #355083 by MathTherapy(10552)\"\" \"About 
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find four consecutive odd integers such that the sum of the first three exceeds the fourth by 18.\r
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\n" ); document.write( "\n" ); document.write( "Let the first of the four consecutive odd integers = F\r
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\n" ); document.write( "\n" ); document.write( "Then others are: F + 2, F + 4, and F + 6\r
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\n" ); document.write( "\n" ); document.write( "We therefore have: F + F + 2 + F + 4 = F + 6 + 18\r
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\n" ); document.write( "\n" ); document.write( "3F + 6 = F + 24\r
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\n" ); document.write( "\n" ); document.write( "3F - F = 24 - 6\r
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\n" ); document.write( "\n" ); document.write( "2F = 18\r
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\n" ); document.write( "\n" ); document.write( "F, or first of the three odd integers = \"18%2F2\", or \"highlight_green%289%29\"\r
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\n" ); document.write( "\n" ); document.write( "Other three are: \"highlight_green%2811_13_and_15%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to MathMadEzy@aol.com
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