document.write( "Question 544383: Here is the question:
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document.write( "The units digit of a two-digit number is 2 less than the square of the tens digit. If 36 is added to the number, the result is the number with the digits reversed. Find the original number.
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document.write( "Thanks! \n" );
document.write( "
Algebra.Com's Answer #355081 by lwsshak3(11628) ![]() You can put this solution on YOUR website! The units digit of a two-digit number is 2 less than the square of the tens digit. If 36 is added to the number, the result is the number with the digits reversed. Find the original number. \n" ); document.write( "** \n" ); document.write( "let u=units digit \n" ); document.write( "let t=tens digit \n" ); document.write( "u=t^2-2 \n" ); document.write( "10t+u+36=10u+t \n" ); document.write( "10t+(t^2-2)+36=10(t^2-2)+t \n" ); document.write( "10t+t^2-2+36=10t^2-20+t \n" ); document.write( "10t+t^2+34=10t^2-20+t \n" ); document.write( "9t^2-9t-54=0 \n" ); document.write( "t^2-t-6=0 \n" ); document.write( "(t-3)(t+2)=0 \n" ); document.write( "t=-2 (reject) \n" ); document.write( "or \n" ); document.write( "t=3 \n" ); document.write( "u=t^2-2=9-2=7 \n" ); document.write( "original number: 37 \n" ); document.write( "Check: 37+36=73 \n" ); document.write( " |