document.write( "Question 544372: Here is the problem I am trying to solve:
\n" ); document.write( "The sum of the digits of a two-digit number is 6. If the digits are reversed, the new number is 9 less than four times the original number. Find the original number.
\n" ); document.write( "Thanks!
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Algebra.Com's Answer #355061 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let the number be xy. x in the tens place.\r
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\n" ); document.write( "\n" ); document.write( "x+y=6------------(1)\r
\n" ); document.write( "\n" ); document.write( "10y+x=4(10x+y)-9
\n" ); document.write( "10y+x=40x+4y-9\r
\n" ); document.write( "\n" ); document.write( "6y-39x=-9------------(2)\r
\n" ); document.write( "\n" ); document.write( "Add equation (1) & (2)\r
\n" ); document.write( "\n" ); document.write( "1.00 x + 1 y = 6 .............1
\n" ); document.write( "-39 x + 6 y = -9 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -6
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-6 x -6 y = -36
\n" ); document.write( "-39 x + 6 y = -9
\n" ); document.write( "Add the two equations
\n" ); document.write( "-45 x = -45.000
\n" ); document.write( "/ -45
\n" ); document.write( "x = 1
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "x + y = 6
\n" ); document.write( " + y = 6
\n" ); document.write( " y = 6 -1
\n" ); document.write( " y = 5
\n" ); document.write( " y = 5 \r
\n" ); document.write( "\n" ); document.write( "The number is 15\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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