document.write( "Question 544056: In a 75 m race if ace gives flash a 15 m head start, ace and flash will tie. If flash gives speedy a 15 m head start, flash and speedy will tie. At these rates how many meters head start should ace give speedy for ace and speedy to tie in a 75 m race? \n" ); document.write( "
Algebra.Com's Answer #355044 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In a 75 m race if ace gives flash a 15 m head start, ace and flash will tie. \n" ); document.write( " If flash gives speedy a 15 m head start, flash and speedy will tie. \n" ); document.write( " At these rates how many meters head start should ace give speedy for ace and speedy to tie in a 75 m race? \n" ); document.write( ": \n" ); document.write( "Let's assign a speed to Ace, 10 m/sec, then find Flashe's speed \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed, let f = Flashe's speed \n" ); document.write( "a's time = f's time \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "75f = 10*60 \n" ); document.write( "f = \n" ); document.write( "f = 8 m/sec is Flashes speed \n" ); document.write( ": \n" ); document.write( "Do the same with Flash and speedy \n" ); document.write( "f's time = s's time \n" ); document.write( " \n" ); document.write( "75s = 8*60 \n" ); document.write( "s = \n" ); document.write( "s = 6.4 m/sec is Speedy's speed \n" ); document.write( ": \n" ); document.write( "Write a time equation for Ace and Speedy \n" ); document.write( "let d = distance covered by speedy while Ace covers 75 m \n" ); document.write( " \n" ); document.write( "10d = 75*6.4 \n" ); document.write( "10d = 480 \n" ); document.write( "d = 48 meters \n" ); document.write( "therefore \n" ); document.write( "Ace should give Speedy 75-48 = 27 m head start for them to finish at the same time \n" ); document.write( " |