document.write( "Question 544173: Please help me understand this. Thanks!\r
\n" ); document.write( "\n" ); document.write( "Solve in interval notation
\n" ); document.write( "(x + 1)/(x-4) ≤ 0
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Algebra.Com's Answer #355041 by lwsshak3(11628)\"\" \"About 
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Please help me understand this. Thanks!
\n" ); document.write( "Solve in interval notation
\n" ); document.write( "(x + 1)/(x-4) ≤ 0
\n" ); document.write( "**
\n" ); document.write( "set factors=0, then solve for x
\n" ); document.write( "x+1=0
\n" ); document.write( "x=-1
\n" ); document.write( "x-4=0
\n" ); document.write( "x=4
\n" ); document.write( "critical points are -1 and 4
\n" ); document.write( "draw a number line with critical points on it
\n" ); document.write( "<...+...-1...-....4....+....>
\n" ); document.write( "solution in interval notation:
\n" ); document.write( "[-1,4] (includes -1 and 4)
\n" ); document.write( "..
\n" ); document.write( "Explanation for number line:
\n" ); document.write( "It is easily seen that for x>4, the function>0. Moving to the left, the sign of each interval switches when we go thru a critical x of odd multiplicity like 1, 3, 5, etc. Given x's are all of multiplicity 1.
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