document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=544152>Question 544152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is six times its width. if the perimiter of the rectangle is 70in, find its area? thanks for your help <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355030 by </B><A HREF=/tutors/aboutme.mpl?userid=friesr><B>friesr(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=friesr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What we know:<BR>\n" );
document.write( "Area = Length X Width<BR>\n" );
document.write( "Perimeter of rectangele = 2(lenghth) * 2(width)<BR>\n" );
document.write( "Perimeter of this rectangle = 70 inches<BR>\n" );
document.write( "---\r<BR>\n" );
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document.write( "Width = x<BR>\n" );
document.write( "Length = 6x<BR>\n" );
document.write( "---\r<BR>\n" );
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document.write( "2(x) + 2(6x) = 70<BR>\n" );
document.write( "2x + 12x = 70<BR>\n" );
document.write( "14x = 70<BR>\n" );
document.write( "x=5<BR>\n" );
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document.write( "Lenght = 5<BR>\n" );
document.write( "Width = 30 (6*5)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Area = 5 * 30 <BR>\n" );
document.write( "Area = 150 in^2<BR>\n" );
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