document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=543980>Question 543980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to do this with the substitution method: Help me please\r<BR>\n" );
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document.write( "3x = 4y<BR>\n" );
document.write( "x = (2y+1)/3\r<BR>\n" );
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document.write( "I know the answer is x=2/3 and y = 1/2 but I don't know the method\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354987 by </B><A HREF=/tutors/aboutme.mpl?userid=umnikmo><B>umnikmo(75)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umnikmo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> from the first we can find x in terms of y: x=4y/3, now we substitute this into second equation, we get:<BR>\n" );
document.write( "4y/3=(2y+1)/3<BR>\n" );
document.write( "we can multiply both sides by 3:<BR>\n" );
document.write( "4y=2y+1<BR>\n" );
document.write( "2y=1<BR>\n" );
document.write( "y=1/2.\r<BR>\n" );
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document.write( "now, as x=4y/3=4*(1/2)/3=2/3\r<BR>\n" );
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document.write( "same as your answers. </SPAN>\n" );
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