document.write( "Question 542082: A coin bank contains only nickels, dimes, and quarters. The value of the 31 coins in the bank is $2.80.There are twice as many nickels as dimes. Find the number of each type of coin in the bank. \r
\n" ); document.write( "\n" ); document.write( "So far I have done: Dimes=x
\n" ); document.write( " Nickels=2x
\n" ); document.write( " Quarters=(31-x)\r
\n" ); document.write( "\n" ); document.write( "Dimes= 10 times x
\n" ); document.write( "Nickels= 5 times 2x
\n" ); document.write( "Quarters= 25 (31-x)\r
\n" ); document.write( "\n" ); document.write( "5(2x)+10x+25(31-x)=280
\n" ); document.write( "10x+10x+775-25x=280<-----doesn't look right. \r
\n" ); document.write( "\n" ); document.write( "I believe I am messing up on the quarters section.
\n" ); document.write( "

Algebra.Com's Answer #354956 by jpg7n16(66)\"\" \"About 
You can put this solution on YOUR website!
\"So far I have done: Dimes=x\" this part is right, though I like to use D for dimes
\n" ); document.write( "\"Nickels=2x\" Again, right.
\n" ); document.write( "\"Quarters=(31-x)\" This is wrong. What you are saying with this equation is that \"Quarters=31-Dimes\". But what about the nickels? should be:
\n" ); document.write( "\"Q=31-d-n=31-d-2d=31-3d\" or in your case
\n" ); document.write( "\"Q=31-3x\"
\n" ); document.write( ".
\n" ); document.write( "\"Dimes= 10 times x\" Correct
\n" ); document.write( "\"Nickels= 5 times 2x\" Correct
\n" ); document.write( "\"Quarters= 25 (31-x)\" Use above formula.
\n" ); document.write( "\"Q=25%2A%2831-3x%29\"
\n" ); document.write( "And solving:
\n" ); document.write( "\"10x%2B5%2A2x%2B25%2A%2831-3x%29=280\"
\n" ); document.write( "\"10x%2B10x%2B775-75x=280\"
\n" ); document.write( "\"-55x=-495\"
\n" ); document.write( "\"x=9\"
\n" ); document.write( "And I believe you've got it from here! Hope this helps
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