document.write( "Question 543342: evaluate the following:\r
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document.write( "sin^-1 (Cos 2pi/3) \n" );
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Algebra.Com's Answer #354949 by lwsshak3(11628) ![]() You can put this solution on YOUR website! evaluate the following: \n" ); document.write( "sin^-1 (Cos 2pi/3) \n" ); document.write( "** \n" ); document.write( "Cos (2π/3) =-1/2 ( reference angle of π/3 in quadrant II where cos<0 \n" ); document.write( "sin^-1 (Cos 2pi/3)=sin^-1 (-1/2)=-π/6 \n" ); document.write( "note: domain of sin^-1 is [-π/2,π/2] \n" ); document.write( " |