document.write( "Question 543751: Mrs. garcia is 1 year less than 3 times as old as her daughter. Seven years from now, she will be 4 years morethan twice as old as her daughter will be then. find both their ages using substitution or elimination please show your work
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Algebra.Com's Answer #354924 by ankor@dixie-net.com(22740)\"\" \"About 
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Let g = Mr's G's present age
\n" ); document.write( "Let d = daughter's present age
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\n" ); document.write( "Write an equation for each statment
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\n" ); document.write( "\"Mrs. garcia is 1 year less than 3 times as old as her daughter.\"
\n" ); document.write( "g = 3d - 1
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\n" ); document.write( "\"Seven years from now, she will be 4 years more than twice as old as her daughter will be then.\"
\n" ); document.write( "g + 7 = 2(d+7) + 4
\n" ); document.write( "g + 7 = 2d + 14 + 4
\n" ); document.write( "g + 7 = 2d + 18
\n" ); document.write( "g = 2d + 18 - 7
\n" ); document.write( "g = 2d + 11
\n" ); document.write( "Substitute (3d-1) for g, (from the 1st equation)
\n" ); document.write( "3d - 1 = 2d + 11
\n" ); document.write( "3d - 2d = 11 + 1
\n" ); document.write( "d = 12 yrs is daughter's present age
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\n" ); document.write( "Find g
\n" ); document.write( "g = 3(12) - 1
\n" ); document.write( "g = 35 yrs is Mrs G's present age
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\n" ); document.write( "Confirm this in the statement
\n" ); document.write( "\"Seven years from now, she will be 4 years more than twice as old as her daughter \"
\n" ); document.write( "35 + 7 = 2(12+7) + 4
\n" ); document.write( "42 = 2(19) + 4
\n" ); document.write( "42 = 38 + 4; confirms our solutions\r
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