document.write( "Question 6409: How do you solve these linear inequalities algebraically?\r
\n" ); document.write( "\n" ); document.write( "3x+4y=5
\n" ); document.write( "Ax+3y=B
\n" ); document.write( "

Algebra.Com's Answer #3549 by Sanskriti(1)\"\" \"About 
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Plug in the point(-3,4) in the equation for x and y.\r
\n" ); document.write( "\n" ); document.write( " A(-3) + B(4) = 11
\n" ); document.write( " -3A + 4B = 11------(1)\r
\n" ); document.write( "\n" ); document.write( " Plug in the point (2,1) in the equation.\r
\n" ); document.write( "\n" ); document.write( " A(2) + B(1) = 11
\n" ); document.write( " 2A + B = 11------(2)\r
\n" ); document.write( "\n" ); document.write( " From (2) 2A + B = 11
\n" ); document.write( " Subtracting 2A on both sides, \r
\n" ); document.write( "\n" ); document.write( " 2A + B – 2A = 11 – 2A
\n" ); document.write( " B = 11 – 2 A\r
\n" ); document.write( "\n" ); document.write( " Plugging this in (1), we get,
\n" ); document.write( " -3A + 4( 11-2A = 11
\n" ); document.write( " -3A + 44 – 8A = 11
\n" ); document.write( " -11A = – 33
\n" ); document.write( " A = 3\r
\n" ); document.write( "\n" ); document.write( " Plug in the value of A in any one of the equation (1) and (2)\r
\n" ); document.write( "\n" ); document.write( " 2A + B = 11
\n" ); document.write( " 2(3) + B = 11
\n" ); document.write( " 6 + B = 11
\n" ); document.write( " B = 11 – 6 = 5.\r
\n" ); document.write( "\n" ); document.write( " So A = 3 and B =5 is the solution.
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