document.write( "Question 543581: Solve for x algebraiclly\r
\n" ); document.write( "\n" ); document.write( "Log base 2 (4) + Log base 2 (x) = 1
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Algebra.Com's Answer #354883 by lwsshak3(11628)\"\" \"About 
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Solve for x algebraiclly
\n" ); document.write( "Log base 2 (4) + Log base 2 (x) = 1
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\n" ); document.write( "Log2 (4) + Log2 (x) = 1
\n" ); document.write( "2+log2(x)=1
\n" ); document.write( "log2(x)=-1
\n" ); document.write( "convert to exponential form: base(2) raised to log of number(-1)=number(x)
\n" ); document.write( "2^-1=x
\n" ); document.write( "x=2^-1=1/2
\n" ); document.write( "x=1/2
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