document.write( "Question 543581: Solve for x algebraiclly\r
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document.write( "Log base 2 (4) + Log base 2 (x) = 1 \n" );
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Algebra.Com's Answer #354883 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve for x algebraiclly \n" ); document.write( "Log base 2 (4) + Log base 2 (x) = 1 \n" ); document.write( "** \n" ); document.write( "Log2 (4) + Log2 (x) = 1 \n" ); document.write( "2+log2(x)=1 \n" ); document.write( "log2(x)=-1 \n" ); document.write( "convert to exponential form: base(2) raised to log of number(-1)=number(x) \n" ); document.write( "2^-1=x \n" ); document.write( "x=2^-1=1/2 \n" ); document.write( "x=1/2 \n" ); document.write( " |