document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=543570>Question 543570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x^2+x=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354852 by </B><A HREF=/tutors/aboutme.mpl?userid=IFY><B>IFY(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IFY><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=IFY><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "    2x^2+x=-1\r<BR>\n" );
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document.write( "    FIRST OF ALL TRY 2 PUT 1 INTO THE LEFT HAND SIDE IN ORDER TO BE FACTORIZED\r<BR>\n" );
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document.write( "   2X^2 +X +1 = 0\r<BR>\n" );
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document.write( "   2X ( X + 1) - 1 (X +1 ) = 0\r<BR>\n" );
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document.write( "     (X +1) (2X - 1)\r<BR>\n" );
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document.write( "  X + 1= 0  ,       2X - 1 = O<BR>\n" );
document.write( "   X = -1     ,     2X = 1... DIVIDE BOTH SIDES BY 2<BR>\n" );
document.write( "   X = - 1    ,          X = 1/2<BR>\n" );
document.write( "   <BR>\n" );
document.write( "    X = - 1 OR 1 / 2 </SPAN>\n" );
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