document.write( "Question 543473: Can you please help me solve this equation?
\n" ); document.write( " $\"+log%28n%2B9%29=+log%284n%29\"$ \r
\n" ); document.write( "\n" ); document.write( "It is the log of ten since it is not stated.
\n" ); document.write( "Do you switch it to exponential form? \n" ); document.write( "

Algebra.Com's Answer #354832 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
log(n+9)= log(4n)
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\n" ); document.write( "Certainly if log(A) = log(B), A must equal B.
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\n" ); document.write( "Your Problem:
\n" ); document.write( "n+9 = 4n
\n" ); document.write( "3n = 9
\n" ); document.write( "n = 3
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\n" ); document.write( "Another way to get to the same answer:
\n" ); document.write( "log(n+9)= log(4n)
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\n" ); document.write( "Write each side as an exponent of 10:
\n" ); document.write( "10^(log(n+9)) = 10^(log(4n))
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\n" ); document.write( "Then n+9 = 4n
\n" ); document.write( "and 3n = 9
\n" ); document.write( "so n = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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